Daggos Posted February 24, 2022 Posted February 24, 2022 Hi, I'm trying to get the average of 5 channels as 1 average for all. How would i go about that? Quote
AzeoTech Posted February 24, 2022 Posted February 24, 2022 For the current average across 5 channels, it is simply: (ChanA[0] + chanB[0] + ChanC[0] + ChanD[0] + ChanE[0]) / 5 Quote
Daggos Posted February 25, 2022 Author Posted February 25, 2022 Sorry was totally overthinking that cheers. Quote
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